我正在尝试使用 eclipselink 将 java 对象保存到 jsonb 列到 Postgres 数据库中，但我现在被困在编写适当的转换器上。任何人都可以帮助我或给我一个使用 eclipselink 在 java 中持久化 jsonb 类型的好例子吗？

这是模型代码：

@Entity
@Table(name = TABLE_NAME)
public class SystemEventModel implements Serializable {

   public static final String TABLE_NAME = "system_event";

   @Id
   @Column(name = "id")
   private Long id;

   @Lob
   @Column(name = "event_data", columnDefinition = "jsonb")
   private JsonObject eventData;

   public SystemEventModel(JsonObject eventData) {
        this.eventData = eventData;
    }       
}

Currently, I just get the error "ERROR: column "event_data" is of type jsonb but the expression is of type bytea" when I try to persist this object. I'm aware why it is but I don't know how to write a converter since I don't understand in what type should I convert the JsonObject type for it to get passed like jsonb.

Here is what I mean in this converter sample:

@Converter(autoApply = true)
public class AppAttributeTypeAttributeConverter implements AttributeConverter<JsonObject, ???> {

    @Override
    public ??? convertToDatabaseColumn(JsonObject eventData) {
        return ???;
    }

    @Override
    public JsonObject convertToEntityAttribute(??? eventData) {
        return ???;
    }
}

And here is snippet for persisting:

    String details = "{ \"pressed\": \"yes\", \"isDefault\": \"true\", \"type\": \"BUTTON\"}";
    JsonReader jsonReader = Json.createReader(new StringReader(details));
    JsonObject jsonObject = jsonReader.readObject();
    jsonReader.close();
    SystemEventModel eventModel = new SystemEventModel(jsonObject);
    em.persist(eventModel);

Thanks in advance!

以下是您可以做的可能有效的事情：

改变

 @Lob
 @Column(name = "event_data", columnDefinition = "jsonb")
 private JsonObject eventData;

到

 @Lob
 @Type(type = "jsonb")
 @Column(name = "event_data", columnDefinition = "jsonb")
 private String eventData;

 public SystemEventModel(String eventData) {
    this.eventData = eventData;
 }

然后坚持使用这个：

String details = "{ \"pressed\": \"yes\", \"isDefault\": \"true\", \"type\": \"BUTTON\"}";
SystemEventModel eventModal = new SystemEventModel(details); // or you can use setter method.
em.persist(eventModel);

我希望它有所帮助！

请参阅如何使用 Hibernate 将 String JPA 属性映射到 JSON 列

谢谢...

编辑：-

  @Override
  public Object convertToDatabaseColumn(JsonObject eventData) {
    try {
      PGobject out = new PGobject();
      out.setType("json");
      out.setValue(eventData.toString());
      return out;
    } catch (Exception e) {
      throw new IllegalArgumentException("Unable to serialize to json field ", e);
    }
  }

  @Override
  public JsonObject convertToEntityAttribute(Object eventData) {
    try {
      if (eventData instanceof PGobject && ((PGobject) eventData).getType().equals("json")) {
        return mapper.reader(new TypeReference<JsonObject>() {
        }).readValue(((PGobject) eventData).getValue());
      }
      return Json.createObjectBuilder().build();
    } catch (IOException e) {
      throw new IllegalArgumentException("Unable to deserialize to json field ", e);
    }
  }

这是我为 JPA 找到的解决方案，而不是专门为 hibernate 或 eclipselink 找到的。

在这里看看：stackoverflow.com/questions/39830842 /...
Thanks! But, this would probably work with Hibernate implementation and is not for EclipseLink.